c^2+3c-c^2+4c=9c-16

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Solution for c^2+3c-c^2+4c=9c-16 equation: 



c^2+3c-c^2+4c=9c-16

We move all terms to the left:

c^2+3c-c^2+4c-(9c-16)=0

We add all the numbers together, and all the variables

7c-(9c-16)=0

We get rid of parentheses

7c-9c+16=0

We add all the numbers together, and all the variables

-2c+16=0

We move all terms containing c to the left, all other terms to the right

-2c=-16

c=-16/-2

c=+8

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